20x^2+x-21=0

Solution for 20x^2+x-21=0 equation:

Simplifying
20x2 + x + -21 = 0

Reorder the terms:
-21 + x + 20x2 = 0

Solving
-21 + x + 20x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-21 + -20x)(1 + -1x) = 0

Subproblem 1
Set the factor '(-21 + -20x)' equal to zero and attempt to solve:

Simplifying
-21 + -20x = 0

Solving
-21 + -20x = 0

Move all terms containing x to the left, all other terms to the right.

Add '21' to each side of the equation.
-21 + 21 + -20x = 0 + 21

Combine like terms: -21 + 21 = 0
0 + -20x = 0 + 21
-20x = 0 + 21

Combine like terms: 0 + 21 = 21
-20x = 21

Divide each side by '-20'.
x = -1.05

Simplifying
x = -1.05
Subproblem 2
Set the factor '(1 + -1x)' equal to zero and attempt to solve:

Simplifying
1 + -1x = 0

Solving
1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1
Solution
x = {-1.05, 1}